Question

In the following diagram , find the potential difference across 4 Ω.

Answer 1

Answer:

16 V

Step-by-step explanation:

First The total resistance in the circuit is

=6+4

=10 ohm

Now the total current in the circuit is given by

$current = \frac{potential \: difference}{total \: resistance} \\ \\ = \frac{40}{10} \\ \\ = 4 \: amperes$

Now we know that In series combination

The current is constant and potential difference varies.

so

$v = v1 + v2 \\ where \: v1 \: and \: v2 \: are \: indivdual \: potential \: differences \: of \: r1 \: and \: r2 \\ \\ so \: by \: ohms \: law \: we \: have \\ v1 = i \times \: r1 \: and \: v2 = i \times \: r2 \: therefore \\ v2 = 4 \times 4 = 16 \: volt$

I hope you are clear if not just comment me and mark me as the brainliest.