In the following diagram resistances are R1 = 15 Ω, R2 = 10 Ω, R3 = 30 Ω, R4 = 5 Ω, R5 = 20 Ω and battery is 18 V. Calculate the total resistance and the electrical current flowing in the circuit.
Answers
Given : R₁ = 15Ω, R₂ = 10Ω,R₃ = 30Ω, R₄ = 5Ω, R₅ = 20Ω and battery is 18 volt.
To Find : total resistance
electrical current flowing in the circuit.
Solution:
R₁ , R₂ and R₃ are in parallel
Hence 1/R₆ = 1/R₁ + 1/R₂ + 1/R₃
=> 1/R₆ = 1/15 + 1/10 + 1/30
=> 1/R₆ = (2 + 3 + 1) /30
=> 1/R₆ = (6) /30
=> 1/R₆ = 1/5
=> R₆ = 5 Ω
R₄ and R₅ are in parallel
=> 1/R₇ = 1/R₄ + 1/R₅
=> 1/R₇ = 1/5 + 1/20
=> 1/R₇ = (4 + 1)/20
=> 1/R₇ = (5)/20
=> 1/R₇ = 1/4
=> R₇ = 4 Ω
R₆ and R₇ are ins series
R = R₆ + R₇
=> R = 5 + 4
=> R = 9 Ω
the total resistance = 9 Ω
I = V/R
=> I = 18/9 = 2A
electrical current flowing in the circuit. = 2A
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