Question

.In the following equation, the value of 'p' and 'q x^2-4x-21=(x+p)(x+q)

Answer 1

Step-by-step explanation:

$x^{2} -4x-21\\\\=x^{2}-7x+3x-21\\\\=x(x-7)+3(x-7)\\ \\=(x+3)(x-7)$Using Splitting the middle term

Therefore after comparing

p = 3

q = (-7)

Hope this helps....

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