Question

In the following equations determine the value of ‘k’ for which the given value is a

solution of the given equation…

a) Kx2 + 2x – 3 = 0, x = 2

b) x

2 + 2ax – k = 0, x = - a​

Answer 1

Step-by-step explanation:

a)

kx²+2x-3=0. x=2

or k.2²+2.2-3=0

or 4k+4-3=0

or 4k+1=0

or k=-1/4

b)

x²+2ax-k=0, x=-a

or (-a)²+2a.(-a)-k=0

or a²-2a²-k=0

or -a²-k=0

or k=-a²