in the following figure 0 is centre of circle find x and y
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x= 17 cm
y= 8.5 cm
Here the triangle is right angled triangle.
By using the Pythagoras theorem we know , square of base and the square of perpendicular height is equl to the square of hypotenuse (b²+p²=h²)
15²+8²=x²
x²=15²+8²
x²=225+64
x²= 289
x=√289
x=17
Since x is the diameter of the semi-circle and y is the to the radius of the semi-circle.
Diameter = Twice the radius
Hence, 17 = 2r
2r= 17
r= 17/2
r= 8.5
Therefore x = 17 and y = 8.5
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