Math, asked by Raaz2345, 10 months ago

In the following figure, a tower AB is 20 m high and BC, its shadow on the ground, is 20√3m long. Find the Sun's altitude.​

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Answered by aman6618
2

Answer:

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Answered by Anonymous
5

\huge\mathbb{SOLUTION:-}

Let AB be the tower and BC be its shadow.

AB = 20, \: BC = 20 \sqrt{3}

In \DeltaABC,

 \tan(\theta)  =  \frac{AB}{BC}

 \tan(\theta)  =  \frac{20}{20 \sqrt{3} }

 \tan(\theta)  =  \frac{1}{ \sqrt{3} }

But, \tan(\theta)  =  \frac{1}{\sqrt{3} }

\therefore \theta = 30

The sun is at an altitude of 30°.

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