Question

In the following figure,
AABC is circumscribed
touching the circle at P,
Q, R if AP= 4 cm, BP =
6 cm, AC = 12 cm, then
find radius of circle.​

Answer 1

Answer:

4 cm

Step-by-step explanation:

AP = AR =4 cm

BP = BQ = 6 cm

AB = AP + PB = 4 + 6 = 10 cm

AC = 12cm

RC = AC - AR = 12 - 4 = 8 cm

RC = QC = 8 cm

BC = BQ + QC = 6 + 8 = 14 cm

inradius of ∆ = (a+b-c)/2

= (10+12-14)/2

= 8/2

= 4 cm