IN THE FOLLOWING FIGURE AB=BC AND AC =84cm.THE RADIUS OF THE INSCRIBED CIRCLE IS 14cm AND B IS THE CENTRE OF LARGEST SEMI-CIRLCE. WHAT IS THE AREA OF THE SHADED REGION
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Answer:
AC = 84 cm
AB = BC =
2AB = 84
AB = 42
Area of circle (semi) whose diameter is AB.
A
1
=πR
2
/2
=π(21)
2
/2=
7
22
×22×21×
2
1
=11×3×21=33×21
=693cm
2
Area of circle (semi) whose diameter is BC
A
2
=
2
πR
2
=693cm
2
Area of circle whose diameter is AC
A=
2
πR
2
=
7
22
×42×42×
2
1
A=
2
5544
cm
2
=2772cm
2
Area of smallest circle
a=πr
2
=
7
22
×14×14=616cm
2
Area of the shaded region = A−(A
1
+A
2
+a)
=2772−(693+693+616)
=2772−2002
770cm
2
Step-by-step explanation:
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