Question

In the following figure, AB,CD, and EF are perpendicular to the straight line BDF. If AB=x and CD=z unit and EF=y unit prove that: 1/x + 1/y=1/z

Answer 1

Answer:

Let BD=a and DF=b. In ∆ABF, CD is parallel to AB

==> CD/AB = DF/BF. i.e., z/x = b/(a+b).

And, in ∆ BEF,CD is parallel to EF

==> CD/EF = BD/BF i.e. z/y = a/(a+b).

so, z/x+z/y = b/(a+b)+a/(a+b) = 1

==> 1/x+1/y=1/z

hence proved

Answer 2

Answer:

answer is in attachment

hope it will help you

Step-by-step explanation:

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