Question

in the following figure, AB is parallel to CD. find the value of X in degrees AB = 110 CD = 30 find X
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Answer 1

Answer:

Draw a line EF perpendicular to AB and CD passing through M

In △BME

∠BME+∠MBE+∠BEM=180

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(Angle sum proprerty)

∠BME+35

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+90

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=180

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∠BME=180

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−125

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∠BME=45

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In △DMF

∠DMF+∠MDF+∠MFD=180

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(Angle sum property )

∠DMF+75

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+90

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=180

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∠DMF=180

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−165

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∠DMF=15

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x=∠DMF+∠BME+∠EMF

x=15

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+45

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+180

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x=240

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