Question

In the following figure ABC and ADC are equilateral triangles find the coordinates of points C and D

Answer 1

Answer:

where is the figure please ask with figure

Answer 2

Answer:

Distance CD= [√(x1-x2) + (y1-y2)]

Step-by-step explanation:

if it forms a parallelogram ∆ABC & ∆ADC are both conguent /equilateral too.

so, AB=CD, AB||CD & BC=DA, BC||DA

Hence,

point C & Point D are valid vertices for coordinates with the distance formula given above. and....If Coordinator for point C is (x1, y1) & D (x2, y2)

But, The question is incomplete.