Question

In the following figure ABC and BDE are two equilateral triangles such that D is the mid-point of

BC. The ratio of the areas of ABC and BDE is_______​

Answer 1

Answer:

1:1 hope this helps you

Answer 2

ABC and BDE are two equilateral triangles such that D is the midpoint of BC

so,BC=2BD

and, area of triangle =√3/4×a²

so, the ratio of areas of ABC and BDE is

ar∆ABC/ar∆BDE=√3/4×a²/√3/4×a²

=√3/4×(2BD)²/√3/4×(BD)²

=√3/4×4BD²/√3/4×BD². [√3/4×BD²/√3/4×BD²]

=4:1

Hence, the ratio of areas of ∆ABC and ∆BDE is 4:1