Question

In the following figure, ABC is an isosceles triangle with AB=AC and angle BAD=28 degree, find angle DAC

Answer 1

the correct answer is 45° , tell if it is correct

Answer 2

Answer: here in the diagram

in ΔABD

∠ABD+∠ADB+∠BAD=180°   (angle sum property)

∠ABD+90°+28°=180°

∠ABD=62°

∵AB=AC    so  ∠ABD=∠ACD= 62°

Again in ΔADC

∠ADC+∠DAC+∠ACD=180°

90°+∠DAC+62°=180°

∠DAC=28°