In the following figure, ABC is an isosceles triangle with AB=AC and angle BAD=28 degree, find angle DAC
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the correct answer is 45° , tell if it is correct
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Answer: here in the diagram
in ΔABD
∠ABD+∠ADB+∠BAD=180° (angle sum property)
∠ABD+90°+28°=180°
∠ABD=62°
∵AB=AC so ∠ABD=∠ACD= 62°
Again in ΔADC
∠ADC+∠DAC+∠ACD=180°
90°+∠DAC+62°=180°
∠DAC=28°
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