Question

in the following figure ABCD is a cyclic quadrilateral whose side area is a diameter of the circle and the point O is the centre of the circle if angle ACD is equal to 50 degrees the measure of the angle angle abc​

Answer 1

Step-by-step explanation:

co = OD then triangle cod is isosceles triangle angle C is equals to angle d then angle D is equals to 50 degree sum of opposite angle of cyclic quadrilateral is 180 degree angle D + Angle B is equals to 180 degree so 50 degree + Angle B is equals to 180 degree then Angle B is equals to 130 degree