Question

In the following figure, ABCD is a parallelogram. Find the values of x, y & z

Answer 1

$\huge\underline\mathfrak\pink{Answer}$

From the figure

AD∥BC,BD is the transversal line

⟹∠ADB=∠DBC (∵alternate angles)

⟹z=30

∘

Also

100

∘

,x are supplementary angles

So x=180

∘

−100

∘

=80

∘

x,y,30

∘

forms a triangle

⟹x+y+30

∘

=180

∘

⟹y=180

∘

−80

∘

−30

∘

=70

∘

Answer 2

Answer:

From the figure

AD∥BC,BD is the transversal line

⟹∠ADB=∠DBC (∵alternate angles)

⟹z=30

∘

Also

100

∘

,x are supplementary angles

So x=180

∘

−100

∘

=80

∘

x,y,30

∘

forms a triangle

⟹x+y+30

∘

=180

∘

⟹y=180

∘

−80

∘

−30

∘

=70

∘