in the following figure ABCD is a rectangle with sides 8 cm and 4 cm find area of triangle ABC and triangle CDA
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area of ABC = 1\2 * b * h
A= 1\2 * 8*4
A= 16 cm^ 2
area of CDA = 1\2 * 8 * 4
A= 16cm^ 2
A= 1\2 * 8*4
A= 16 cm^ 2
area of CDA = 1\2 * 8 * 4
A= 16cm^ 2
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