Question

in the following figure ,ABCD is a rectangle with sides 8cm and 4 cm. find the area of ABC and CDA​

Answer 1

Step-by-step explanation:

Area of triangle is 1/2 × b× h.

But it divideds in to two triangles 1/2 × b× h.

1/2 × 8 × 4 = 16 cmsq

ABC is 16 cmsq.

CDA is 16 cmsq.

Hope it helps you .

Answer 2

⇒ Given Figure:

A rectangle ABCD with measures of length and breadth as 8 cm and 4 cm respectively. Diagonal AC is marked.

Please refer the attachment to view the figure.

⇒ To Find:

The area of ΔABC and ΔCDA.

⇒ Solution:

First, we can find the area of ΔABC.

ΔABC is a right angled triangle with:

Altitude = 4 cm

Base = 8 cm

$\bf{\implies\:Area=\dfrac{1}{2}\times\:base\times\:height}$

$\sf{=\dfrac{1}{2}\times8\times4}$

$\sf{=8\times2}$

$\sf{=16\:cm^2}$

The area of ΔABC is 16 cm².

The same area can be substituted for ΔCDA as two triangles formed by the same diagonal inside a rectangle have equal area.

So:

ΔABC = 16 cm²

ΔCDA = 16 cm²