In the following figure. ABCD is a rhombus. Find the values of x and y.
D
С
5x - 3
х
2y-1
60°
A
4x + 3
B
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Step-by-step explanation:
since it is a rhombus
sides will be equal
so
5x-3=4x+3
x= 6
now by cosine law
BD²=AD²+AB²-2AD.AB cosø
(2y-1)²=(5x-3)²+(4x+3)²-2(5x-3)(4x+3)cos60
(2y-1)²=27²+27²-(2×27²×1/2)
(2y-1)²=2×27²-27²
(2y-1)²=27²
2y-1=27
2y=28==> y=14
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