Question

In the following figure ABCD is a square and its two diagonal intersect at O.if area of triangle OAB is 4cm square find the sida of the square​

Answer 1

Answer:

area of one triangle=4cm

then,

there are 4 triangles in the square

so,

add all triangle's area=oab+OBC+OCD+oda

=4cm+4cm+4cm+4cm

=16cm

then area of square=16cm

side *side =16cm

side sq.=16

=√16

=√4*4

side=4cm

Step-by-step explanation:

all side of square is equal .so there is two diagonals it will also be equal.

GIVEN-area of oab is 4 cm sq.

there are 4 triangles in the square.so,the area of all 4 triangles will be equal.

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