in the following figure ABCD is a square and its two diagonals intersect at O if area of triangle ABC is 4 centimetre square find the side of a square
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side of square = 2√2 cm if ABCD is a square and its two diagonals intersect at O and area of triangle ABC is 4 centimetre square
Step-by-step explanation:
a square has all sides equal and all angles right angle
hence abc is an isosceles right angle triangle.
let say side of square = a
area of triangle abc = (1/2)ab × bc
= (1/2) × a × a
(1/2) × a × a = 4
a^2 = 8
a = 2root2
side of square = 2√2 cm
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