in the following, figure, ABCDE is a regular pentagon.the sides AB and DC are produced to meet at F. find the angles x y z
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Answer:
x = 36°, y = 36°, z = 72°
Step-by-step explanation:
As we know,
'All inner angles of a regular pentagon value 108°'
∵ ∠B = 108°
Pentagon consists of 3 parts and therefore, each angle values;
108/3 = 36°
∵ y = 36° (since ∠B = 3y)
ΔEBD is an isosceles Δ and as we know, sum of all the angles of a triangle = 180°
∵ y + z + ∠DEB = 180°
Since isosceles triangles has two equal sides,
z = ∠DEB
⇒ y + z + z = 180°
⇒ y + 2z = 180°
By putting the value of y in the above equation,
36° + 2z = 180°
2z = 180° - 36°
z = 144°/2
z = 72°
Now, x and y are alternate angles
∵ x = y = 36° (alternate angles are equal)
Thus, x = 36°, y = 36° , and z = 72°
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