Question

In the following figure AE = BC and AE parallel to BC.If AB=ED=CD and angle A = 102 degree. Then find angle BCD..
Plzzz answer fast i will mark it as brainliest

Answer 1

HEY DEAR ... ✌️

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As the figure ,


∠a+∠b=180°


so,∠b=78°


∠ECD=78°(since ab ║ce)


∠CED=78°


∠AED=24°


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HOPE , IT HELPS ... ✌️

Answer 2

HEY BUDDY,

/_a+/_b=180
/_a=180-102
/_a=78
/_ECD=/_CED=78 (AB||CE)
/_AED=24


HOPE IT HELPS YOU.
BE BRAINLY.