Question

In the following figure, AE bisects $\angle$ CAD and $\angle$ B $=$ $\angle$ C: Find the value of $\angle$ EAC $+$ $\angle$ CAB $+$ $\angle$ ABC. $\degree$

Answer 1

Is this a joke? Even you cannot understand this

Answer 2

Answer:

Step-by-step explanation:

Angle DAE = angle EAC

Angle ABC = angle ACB

DAE + EAC = ABC plus ACB

2* DAE = 2*ABC

angle EAC + CAB + ABC

= angle EAC + BAC + CBA

= 180

AE || BC