In the following figure, AE bisects $\angle$ CAD and $\angle$ B $=$ $\angle$ C: Find the value of $\angle$ EAC $+$ $\angle$ CAB $+$ $\angle$ ABC. $\degree$
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Is this a joke? Even you cannot understand this
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Answer:
Step-by-step explanation:
Angle DAE = angle EAC
Angle ABC = angle ACB
DAE + EAC = ABC plus ACB
2* DAE = 2*ABC
angle EAC + CAB + ABC
= angle EAC + BAC + CBA
= 180
AE || BC
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