Question

in the following figure angle acb = 90 degree, ab = x + 8 cm, bc = x + 1 cm and ac = x + 15cm find the lengths of the sides of the triangle​

Answer 1

Answer is in the attachment

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Answer 2

Answer:

Pythagorean theorem

h² = b² +p²

ac² = ba² + bc²

(x+15)² = (x+8)² + (x+1)²

x² + 225 + 30x = x² + 64 + 16x + x² + 1 + 2x

x² + 225 + 30x = 2x² + 18x + 65

225-65+ 30x - 18x = 2x² - x²

160 + 12x - x² = 0

x² - 12x -160 = 0

x² - (20x-8x) - 160 = 0

x² - 20x + 8x - 160 = 0

x(x-20) +8(x - 20) = 0

(x-20) (x+8)=0

so x = 20, not -8 because its negative term

sides are

ab = x+8= 20+8 = 28 cm

ab = x+8= 20+8 = 28 cmbc =x+1= 20+1 = 21 cm

ab = x+8= 20+8 = 28 cmbc =x+1= 20+1 = 21 cmac = x+15 =20+15 = 35 cm

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