Question

in the following figure, AOB is a straight line ,angle BOC= 60 degree and OD is the bisector of angle AOC. find the value of x​

Answer 1

Answer:

answer 240

Step-by-step explanation:

angle BOC=60°

OD is a bisector of AOC

FIND X

x+x+60=180

2x+60=180

2x=180-60

2x=120

x=60

put value

60+60+60=240answer

Answer 2

Answer:

Step-by-step explanation:

∠AOD + ∠DOC + ∠COB = 180 ° (linear pair)

2∠AOD + ∠COB = 180° (as OD is bisector of ∠AOC hence it divides it into 2 equal parts )

2∠AOD + 60° = 180°

2∠AOD = 120°

∠AOD = 60°

Also, ∠DOC = 60° as ∠AOD = ∠DOC (because OD is bisector of ∠AOC hence it divides it into 2 equal parts )

x =

∠AOD + ∠DOC + x = 360° (reflex angle)

60° + 60° + x = 360°

120° + x = 360°

x = 360° - 120°

x = 240°

Therefore value of x= 240°