Question

in the following figure as per the information given are the triangle prq and triangle aed similar? justify your answer​

Answer 1

Answer:

Since the line segment CD is bisected by AB at O. OC=OD.

In ΔACD, We have OC=OD.

So, AO is the median of ΔACD

Also we know that median divides a triangle into two triangles of equal areas.

∴ar(ΔAOC)=ar(ΔAOD) _______ (1)

Similarly , In ΔBCD,

BO is the median. (CD bisected by AB at O)

∴ar(ΔBOC)=ar(ΔBOD) _______ (2)

On adding equation (1) and (2) we get,

ar(ΔAOC)+ar(ΔBOC)=ar(ΔAOD)+ar(ΔBOD)

∴ar(ΔABC)=ar(ΔABD

hope it helps u !!

Answer 2

$\huge{\textbf{\textsf{\pink{Answer\::}}}}$

Here,

$\bigstar\:\bf\red{\dfrac{PR}{AE}~=~\dfrac{QR}{DE}~=~\dfrac{PQ}{AD}~}$

That's why,

• ∆PRQ & ∆AED are similar.