Question

In the following figure BC =CA and ∆A=20 then ∆ACD is equal to
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Answer 1

Answer:

The correct answer is angleACD=80°

Answer 2

BC =CA ....(given)

$\angle{A}$ = 20°

:. $\angle{B}$ = 20° ....(BC =CA)

$\angle{ACB}$ = 180°–20°–20°

$\angle{ACB}$ = 140°

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