Question

In the following figure FD parallel to BC parallel to AC parallel and AC parallel to ED find x​

Answer 1

Answer:

Answer

Correct option is

A

52

o

Given, AB=AC

∠ABC=∠ACB=x (Isosceles triangle property)

∠BAF=∠ABC+∠ACB

128=x+x

2x=128

x=64

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∠ABC=∠ACB=64

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GIven, DE∥BC,

∠ABC=∠ADE=64 (Corresponding angles)

In △BDC,

BC=CD (Given)

Thus, ∠BDC=∠DBC=64

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Now, ∠ADE+∠CDE+∠BDC=180

64+∠CDE+64=180

∠CDE=52

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