Question

in the following figure find angle DAC​

Answer 1

Answer:

∠DAC = 40°

Step-by-step explanation:

∠ABD = 180 - 123 = 57° (Linear Pair)

As ΔABD is isosceles,

∠ABD = ∠ADB = 57°

Now,

∠ADB + ∠ADC = 180°   (Linear Pair)

∠ADC = 180 - 57 = 123°

By Angle Sum Property of ΔADC,

∠ADC + ∠DCA + ∠DAC = 180°

123 + 17 + ∠DAC = 180°

140 + ∠DAC = 180°

∠DAC = 40°

Answer 2

Answer:

angle DAC =40°

Step-by-step explanation:

Triangle ABD is issoseles triangle. so, angle B = angle D

Then ,Triangle DAC

Given, angle ACD=17°

so,we know that sun of all angles of Triangle is 180°.

if angle D =angle B

than,angle D is equal to 123°

so, angle ADC + angle DCA + angle DAC =180°

123°+17°+angle DCA =180°

140° + angle DCA = 180°

angle DCA = 180° - 140°

angle DCA = 40°