in the following figure, find the area of
shaded portion
plss give answer
Answers
Step-by-step explanation:
Coming to the side UQ using Pythagoras theorem
UQ² = sqrt (UR² + RQ²)
= sqrt (20² + 40²)
= sqrt (400 + 1600)
= sqrt (2000)
UQ = 44.72 cm
Coming to the side TU using Pythagoras theorem
TU² = sqrt (SU² + ST²)
= sqrt (20² + 20²)
= sqrt (400 + 400)
= sqrt (800)
TU = 28.28cm
Coming to the side TQ using Pythagoras theorem
TQ² = sqrt (PQ² + PT²)
= sqrt (20² + 40²)
= sqrt (400 + 1600)
= sqrt (2000)
TQ = 44.72 cm
As we have found the three sides, we move on to find the area.
Semiperimeter = 62.86
I have rounded of for all values to make the sum simpler
Area = sqrt (63(63-45)(63-45)(63-28))
= sqrt (63×18×18×35)
= sqrt (7×9×9×2×9×2×7×5)
= 7×9×2×3 (5)^½
Area of the given triangle = 378 (5)^½
Give a thanks if you are satisfied