Question

in the following figure , if 0 is the centre of the circles and ∠ACB=50°, then find X

plzz answer the question ​

Answer 1

$\mathcal { \orange{SOL:-}}$

∠ACB = 1/2 arc(AB) ..inscribed angle theorem

50° = 1/2 arc(AB)

100° = arc(AB)

$\tt {\red{now, }}$

∠AOB = arc(AB) .....central angle

∠AOB = 100°

arc(AB) + arc(ACB) = 360° ....full circle

100° + arc (ACB) = 360°

arc(ACB) = 360° - 100°

arc(ACB) = 260°

arc (ACB) = x ....central angle

x = 260°