In the following figure, if AB ||CD and angle 1 = 80°, find other angles
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Answered by
8
Answer:
∠1=∠3(vertically opposite angles are equal )
∠4=180 -∠1 (linear pairs are supplementary)
=100°
∠6 =∠2 (corresponding angles are equal )
∠5=∠1 (,, ,,)
∠7 =∠3 (,, ,,)
∠8 =∠4(,, ,,)
hope this helps
Answered by
16
Hey mate
Here is your answer
From the figure; Ang 1=80° ...(1)
Angle 3= 80° ( Vertically opposite angle) ...(2)
Angle 3= Angle 5 ( Alternate interior angle)
=> Angle 5=80° ... (3)
Angle 5= Angle 7 ( Vertically opposite angle)
=> Angle 7=80° ... (4)
Now..
Angle 2
Angle 2+ Angle 1=180° ( Linear pair)
Angle 2+80°=180°
Angle 2=100° ....(5)
Angle 2= Angle 4 (Vertically opposite angle)
=> Angle 4=100° ...(6)
Angle 4= Angle 6 (Alternate interior Angle)
=> Angle 6= 100° ... (7)
Angle 6= Angle 8 ( Vertically opposite angle)
=> Angle 8 =100° ... (8)
Hence from eq. (1) to eq. (8)
We conclude that
Angle 1=3=5=7= 80°
Angle 2=4=6=8=100°
hope it helps
✌✌✌
❤❤❤Advance Happy New year ❤❤❤
Here is your answer
From the figure; Ang 1=80° ...(1)
Angle 3= 80° ( Vertically opposite angle) ...(2)
Angle 3= Angle 5 ( Alternate interior angle)
=> Angle 5=80° ... (3)
Angle 5= Angle 7 ( Vertically opposite angle)
=> Angle 7=80° ... (4)
Now..
Angle 2
Angle 2+ Angle 1=180° ( Linear pair)
Angle 2+80°=180°
Angle 2=100° ....(5)
Angle 2= Angle 4 (Vertically opposite angle)
=> Angle 4=100° ...(6)
Angle 4= Angle 6 (Alternate interior Angle)
=> Angle 6= 100° ... (7)
Angle 6= Angle 8 ( Vertically opposite angle)
=> Angle 8 =100° ... (8)
Hence from eq. (1) to eq. (8)
We conclude that
Angle 1=3=5=7= 80°
Angle 2=4=6=8=100°
hope it helps
✌✌✌
❤❤❤Advance Happy New year ❤❤❤
RagaviRagavendra:
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