Question

In the following figure, if AB ||CD, APQ = 55° and

PRD = 135
find.xº and y
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Answer 1

Step-by-step explanation:

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=> X = 55° [ Adjective Angle ]

=> Angel of PRQ = 180 - 135 = 45°

=> y = 180 - 45 + 55

=> y = 80°

Answer 2

Step-by-step explanation:

ANGLE qpr=180-135=45°

sum of angles of a line=180°

55+45+y=180

105+y=180

y=75°

135=x+y{exterior angle theorum}

135=x+75

x=60°

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