In the following figure,
if AB is parallel to CD, angle APQ=64 degree and angle PRD =125 degrees find the value of x
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9 degree = X.
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Given : AB is parallel to CD, angle APQ=64 ° and angle PRD =125°
To Find : value of x and y
Solution:
Given AB || CD and PQ is transversal
Hence x = 64° ( alternate angle )
125° = x + y as Exterior angle of triangle = sum of two opposite interior angles
=> 125° = 64° + y
=> y = 61°
x = 64° and y = 61°
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