in the following figure, if DE||BC, find x,y and z
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DE parallel to BC and AB is a transversal.
∴ ∠ADE=∠DBE⋯⋯[corresponding angles]
⇒ x=30
o
Now, DE parallel to BC and AC is a transversal.
∴ ∠AED=∠ECB⋯⋯[corresponding angles]
⇒ y=40
o
In triangle ABC,
∠A+∠B+∠C=180
o
⇒ z+30
o
+40
o
=180
o
⇒ z=180
o
−40
o
−30
o
⇒ z=110
o
Therefore,
⇒ x=30
o
⇒ y=40
o
⇒ z=110
o
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