Question

- In the following figure, lines AD, CF and BE intersect at point O. Find the value of y.

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Answer 1

Step-by-step explanation:

Value of y is 20..

2y+2y+3y+3y+4y+4y=360

18y=360

Y=360/18

Y=20

Answer 2

Along line segment BE,

2y + ∠COD + 4y = 180° -------(i)

Along line segment CF,

2y + ∠AOB + 3y = 180° -------(ii)

Adding equation (i) & (ii), we get,

(2y + ∠AOB + ∠COD) + 2y + 4y + 3y = 360°

→ 180° + 2y + 4y + 3y = 360°

→ 9y = 180°

→ y = 20°