Question

In the following figure, O is the centre of the circle, angle AOB= 60 and angle BDC= 100 find angle OBC​

Answer 1

Answer:

angle OBC=60°

Step-by-step explanation:

angle ODA is 100°. (vertically opposite angle)

in triangle ODA

angle O+ angle D+angle A=180°

60+100+angle A=180

angle A=180-160

angle A=20°

So, angle DCB=angle DAO=20° (Alternate angle)

in triangle DCB

angle D+ angle C+ angle B=180

100+20+angle B=180

angle B=180-120

angle B=60