In the following figure PQRS is a square . Diagonal PR and QS meet at point O . If PO=2.5 cm QS=4x-3
Find
1) The Value of x
2)m∠POQ
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To find ∠PQO and ∠PSQ.
PQRS is a rectangle, and O is the intersection point of diagonals PR and SQ.
PR=SQ [Diagonals of rectangle are equal]
PO=Qo [Diagonals of rectangle bisect each other]
∴∠PQO=∠OPQ→(1) [Angles opposite to equal sides]
In △POQ ,
∠PQO+∠POQ+∠OPQ=180∘
2∠PQO+110∘=180∘ [From (1)]
∠PQO=2180∘−110∘=35∘
Now, in △PQS
∠PQS+∠QPS+∠PSQ=180∘
35∘+90∘+∠PSQ=180∘
∠PSQ=180∘−125∘=55∘
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