In the following figure, PQRS is a trapezium with PQ||RS. The bisectors of angle P and angle Q meet at M on side RS such that angle PMQ = 80°. If PM = QM, then show that angle S + angle R = 200°.
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Answer:
100∘
Step-by-step explanation:
In the trapezium PQRS, ∠P +∠S = 180 ∘ (Supplementary angles)
∠S = 180 ∘
−70 ∘
=110 ∘
∠Q + ∠R = 180 ∘
(Supplementary angles)
∠R = 180 ∘ −80 ∘= 100
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