In the following figure PR is perpendicular to QS. PR= 14cm, QR=15 cm and QS =12 cm. What is the perimeter of PQR?
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oohsstudent:
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given that, QR=15,
QS=12
THEREFORE, SR^2=QR^2-QS^2
(BY PYTHAGORAS THEOREM)
SR^2=225-144=81
SR=9
PR=14
THEREFORE, PS=5
now,
pq^2=ps^2+qs^2
pq^2=25+144=169
pq=13
now perimeter=pq+pr+qr
=15+14+13=42cm
QS=12
THEREFORE, SR^2=QR^2-QS^2
(BY PYTHAGORAS THEOREM)
SR^2=225-144=81
SR=9
PR=14
THEREFORE, PS=5
now,
pq^2=ps^2+qs^2
pq^2=25+144=169
pq=13
now perimeter=pq+pr+qr
=15+14+13=42cm
Thanks!
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