Question

In the following figure PR =RS and ZPRQ =ZSRQ. Prove that ∆PQR congruent ∆SQR​

Answer 1

Answer:

by SSS rule ∆PQR &∆SQR are congrent

PR = PS

QR is a common side

if two sides are same the other side must be equal so,PQ = QS

Step-by-step explanation:

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Answer 2

Given -

$\sf \: i) \: PR = \: RS \\ \sf \: ii) \: \angle \: PRQ = \angle \: SRQ$

To prove -

$\sf \triangle \: PQR \cong \triangle \: SRQ$

Proof -

$\sf \: In \triangle \: PQR \: and \: \triangle \: SRQ , \\ \\ \sf \: PR =RS \: (given) \\ \sf \angle \: PRQ = \angle \: SRQ \: (given) \\ \sf \: QR = QR \: (common) \\ \\ \sf \therefore \: \triangle \: PQR \cong \triangle \: SRQ \: </u></strong><strong><u>\: \: \: \green{....proved}$

By (S.A.S)