Question

In the following figure QS is the diameter and O is the cantre of the circle 1APT is the tangent at P Find angle APQ​

Answer 1

Given  : QS is the diameter and O is the centre of the circle  APT is the tangent at P

To  Find : angle APQ​

Solution:

Join OP

in ΔQOP

OP = OQ  = Radius as O is center

=> ∠OQP = ∠OPQ

∠OQP =  30°

=> ∠OPQ = 30°

∠APO = ∠APQ + ∠OPQ

∠APO = 90°  as APT is tangent

=> 90° =  ∠APQ +  30°

=> ∠APQ  = 60°

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