Question

In the following figure QS = SR, QU = SU, PW = WS, ST || RV Find the value of (area of PSX) /(area of PQR) is equal to
(a)1/5
(b)1/6
(c)1/7​

Answer 1

Answer:

(a) 1/5

Step-by-step explanation:

Area of triangle PUS/Area of triangle PQR = 1/4..eqn .(1).....As height remains same but the base of PUS ( SU = 1/4 of QR based on conditions given)

Al we want to find is Ratio of Area of triangle PSX to Area of triangle PQR..

Now we if get how area of PSX is related to area of PUS then thats it.

Condider line PU..its divided in such a way that .. PY = YX and XU = PY/2....This you get as parallel lines divide the adjacent lines in same ratio..

( TQ is divided in half if you draw a line from point U towards PQ and parallel to TS ..Since TQ = VT = VP ..so you know how XU is related to line PU ..Simple similar triangle property gives this)

So we get 5*Area of PSX = 4*Area of PUS..

Thus original ratio as asked now becomes = 1/5

Please mark it as the brainliest answer!!

Answer 2

Answer:

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