Question

in the following figure RP:PK =3:2 find the value of A(trangleTRP) : A(triangleTPK)​

Answer 1

Answer:

Since we have given that

RP : PK = 3:2

So, we can rewrite it as   RP/PK= 3/2

We need to find the ratio of Ar(ΔTRP) : Ar(ΔTPK)

As we know the Area similarity formula:

So, we get that

A(∆TRP) = (1/2) × RP × TM

A(∆TPK) = (1/2) × PK × TM

Hence, the required ratio is 9:4.

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Answer 2

Answer:

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