Question

In the following figure. RPPK 3:2, find the value of A(TRP) : A(TPK)​

Answer 1

Answer:

Ratio of the areas of two triangles with

common or equal heights is equal to the

ratio of their corresponding bases.

A(△TRP)  / A(△TPK)  =  RP/PK

                                  =  3/2

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