In the following figure, show that ΔPSQ ≅ΔPSR.
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PQ=PR=6.5 cm
∆PSQ =∆PSR =90°
Hence Proved,∆PSQ=∆PSR By SAS
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Given : Two triangles namely PSQ and PSR
PQ= 6.5 cm
PR= 6.5 cm
To proof: Triangle PQR and PSR are congruent
Solution :
congruence is property by which two triangles are congruent by any four property that is RHS,SAS,SSS,ASA.
In triangle PQR and Triangle PSR
PQ=PR = 6.5 cm (given) (side)
Angle PSQ = Angle PSR =90° ( Right angle)
PS=PS (SIDE IS COMMON)
TRIANGLE PQR IS CONGRUENT TO PSR
TRIANGLE PQR IS CONGRUENT TO PSR (by RHS congruence property)
Hence ,it is proved that Triangle PQR is congruent to Triangle PSR.
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