Question

In the following figure, the lenght of rod AB is L. A weight of 1000 kg is suspended from the two ends with the help of two Strings of length L. The tension in the rod with be

Answer 1

Answer:

Step-by-step explanation:

Whenever load is being suspended from a rod using the strings, as the load is being exerted upon a force of mg it offers a opposite force in the form of tension. Now this force will get distributed in the road that will form a deformation in the rod due to the load suspended but the tension in the rod will resist the load to deformation via it's tension.

So factually the net tension in the rope or string is going into the rod.

For calculating the tension in the string we have the weight of the two substances which is mg

Weight on the load is= 1000N*10= 10000KN

Now there are two loads which are acting resulting in two tension forces T1 and T2 thus the net tension on the rod

10000+10000= 20000KN

Answer 2

$5000 \div \sqrt{3}$