Math, asked by YashST123, 1 month ago

In the following figure the point A is the centre of the circle. Li∆ABC and ∆DEF are equilateral triangles. If A(∆ABC):A(∆DEF) = 1:2 and AB =4 then what is the length of DE? *ne MN is a tangent at pointM.If AN=14 and MN =7cm determine the radius of the circle​

Answers

Answered by ut42552
0

Answer:

The answer is 45

1:2+4 then 5(-67+45)77363

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