Question

In the following figure, the pulley P1 is fixed and the pulley P2 is movable
to the other end of rope a mass of m1 = 10 kg is attached as shown in
figure in equilibrium condition tension in the thread attached with m2 is
(A) 141 N
(B) 100 N
(C) 80 N
(D) 75 N

answer in full steps!!
best will be marked as brainliest!​

Answer 1

Answer:

tension in the string connecting M2 = 200 N

Explanation:

Given that,

M1 of mass 10 kg attached to a fixed pulley

and M2 is the attached to a movable pulley with its centre

so,

let the tension in M1 mass be T

and so tension in M2 mass that is attached to the movable pulley will 2T

given that,

the whole system is in equalibrium

so,

tension of the string will be equal to the force applied by the gravitation upon mass

so,

for mass M2

2T = M2g

and for mass M1

T = 10g

T = 100 N

so,

2T = M2g

2(100) = 10M2

M2 = 20 kg

now,

tension in the M2 = 2T

= 2(100)

= 200 N

so,

tension in the string connecting M2 = 200 N

Answer 2

Answer:

tension in the string of M2 = 200 N

Explanation:

explanation refer to the attachment