In the following figure, the side BC of
triangle ABC is extended up to the point D.
If angle is equal to 55° and <B = 60°, then
the measure of <ACB is
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Given:-
- Measure of ∠B is 60°.
- Measure of ∠A is 55°.
To find:-
- Measure of ∠ACB.
Solution:-
By First method.
We know that,
Sum of all interior angles of triangle is 180°.
So,
⇒ ∠ACB + ∠A + ∠B = 180°
⇒ ∠ACB + 55° + 60° = 180°
⇒ ∠ACB + 115° = 180°
⇒ ∠ACB = 180° - 115°
⇒ ∠ACB = 65°
Therefore,
∠ACB is 65°
By second method:-
We know that,
Sum of any two interior angles of triangle equal to opposite exterior exterior.
⇒ ∠ACD = ∠A + ∠B
⇒ ∠ACD = 55° + 60°
⇒ ∠ACD = 115°.
And we also know that,
Sum of all angles forms on straight line is equal to 180°. This statement is also known as linear pair.
So,
⇒ ∠ACD + ∠ACB = 180° [Linear pair]
⇒ 115° + ∠ACB = 180°
⇒ ∠ACB = 180° - 115°
⇒ ∠ACB = 65°
Therefore,
∠ACB is 65°.
______________________
∠ACB is 65°
∠ACD is 115°
Answered by
9
Answer:
Step-by-step explanations :
<A = 55°
<B = 60°
So , we should add
55° + 60° =115°
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